optimize generate()
Before we masked all except the removed cell rows, then unmasked all rows on every removal attempt. Now, we mask all except the removed cell rows once each attempt in an order such that we can simply unmask the last (values - 1) rows to try the next cell. An unmask/remask cycle is only required when a removal attempt fails.
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@ -144,17 +144,14 @@ export class SudokuMath {
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generateComplete(): [number[], number] {
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const result = this._baseBoard();
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const [header] = this.getDLXHeader(result, true);
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const callback = (solution: DNode[]) => {
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const dlx = new DLX(header, (solution: DNode[]) => {
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solution.forEach((node) => {
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const meta: NodeMeta = node.meta;
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result[meta.index] = meta.value;
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});
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// return the first solution
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// stop after the first solution
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return true;
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};
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const dlx = new DLX(header, callback);
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});
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dlx.search();
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return [result, dlx.updates];
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@ -176,10 +173,6 @@ export class SudokuMath {
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candidates[meta.index][meta.value - 1] = node;
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});
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// board positions which have been removed
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const removed = new Set<number>();
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const masked: DNode[] = [];
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const hasOneSolution = () => {
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solutions = 0;
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dlx.search();
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@ -187,51 +180,81 @@ export class SudokuMath {
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return solutions === 1;
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};
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const mask = () => {
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// mask all DLX rows which are nullified by existing values
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for (let n = 0; n < this.values2; n++) {
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if (removed.has(n)) {
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continue;
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}
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const nodes = candidates[n];
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const start = Date.now();
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const elapsed = () => Date.now() - start;
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// masked rows in the order they were masked
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const masked: DNode[] = [];
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const maskAtIdx = (idx: number) => {
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const nodes = candidates[idx];
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nodes.forEach((node) => {
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if (node.meta.value !== completed[n]) {
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if (node.meta.value !== completed[idx]) {
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masked.push(node);
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maskRow(node);
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}
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});
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};
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const removed = new Set<number>();
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const removeable = Array.from(this.indexes);
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const maskUpto = (n: number) => {
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for (let j = 0; j < n; j++) {
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// process up to what we've handled
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const idx = removeable[j];
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if (removed.has(idx)) {
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// if we've removed this cell, do not mask it
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continue;
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}
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// otherwise, we had given up it; mask it leaving the original value
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// we won't try this cell again
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maskAtIdx(idx);
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}
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for (let j = this.values2 - 1; j >= n; j--) {
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// for all those we haven't handled, mask leaving the original values
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// for us to to attempt to unmask one cell at a time
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maskAtIdx(removeable[j]);
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}
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};
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const unmask = () => {
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// unmask all DLX rows
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while (masked.length > 0) {
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const unmaskAll = () => {
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let node;
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while ((node = masked.pop())) {
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unmaskRow(node);
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}
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};
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const unmaskNextCell = () => {
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for (let j = 0; j < this.values - 1; j++) {
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unmaskRow(masked.pop()!);
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}
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};
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const start = Date.now();
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const elapsed = () => Date.now() - start;
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const removeable = Array.from(this.indexes);
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const attempt = () => {
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// attempt remove cells until 'clues' cells remain
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shuffle(removeable);
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for (let n = 0; n < this.values2; n++) {
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maskUpto(0);
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for (let i = 0; i < this.values2; i++) {
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if (elapsed() > totalTime || this.values2 - removed.size == clues) {
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break;
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}
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let toRemove = removeable[n];
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removed.add(toRemove);
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mask();
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unmaskNextCell();
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if (!hasOneSolution()) {
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removed.delete(toRemove);
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// failed attempt. prepare for next
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unmaskAll();
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maskUpto(i + 1);
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continue;
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}
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unmask();
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removed.add(removeable[i]);
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}
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unmaskAll();
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};
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while (
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